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Alright, here is the derivatives problem. I couldn't make it easy, I hope you realize, hon. :P

Consider the function given by:

Show that

for any n greater than or equal to zero.

(And f with a superscript mark represents the number of derivatives from f(x).)

If the world should blow itself up,the last audible voice would be an expert saying it can't be done

This post was edited by Hawkeye on Mar 27, 2006.

Http://www.sosmath.com/calculus/diff/derpro01/answer6.html

Since nobody wants to take a crack at it, you've defenestrated your chances of trying. Here you are. :P

Challenging but not impossible.

It is really only a matter of getting a formula in terms of f''(x), f'(x) and f(x), and proving that, then show by induction that if fn+2(x), fn+1(x), and fn(x) is true, then fn+3(x), fn+2(x), fn+1(x) is also true.

If the world should blow itself up,the last audible voice would be an expert saying it can't be done